Ultimate Bullseye Formula

Somebody needs to figure out a/the formula for ultimate bullseye... it must be something to do with the ammount of power, angle of the arrow, height and distance of the board... Any good mathamatitions around? If we had a formula it would make programing a script easy.

I'm gunna try my best to figure something out... Although it would have to be a miracle for me to find anything

 

I concur

 

xD

I've been waiting for someone to reply to this topic for days... And that's what you come up with?

 

xD I'm no genius

 

ll I know is always do punchbag with fire ring and bullseye with closer. Thats how I win.

 

dude I can;t even get 1 bullseye to get the boost thingies o_o

Gimme tips!

 

well if you type catapult to get a free powerup, if you have fire ring, if you hit the 5 you get a power up, if you hit the bullseye you get 2 I think. Bob gives you a power up if you hit the apple and if you get closer it's easy to hit the bullseye.

2nd Post:

and the big bullseye is really easy to hit.

Do not double post. Use the 'edit' button instead.
~L_scoprio

 

Do you go for straight and powerful shots or up and down ones?

 

I go for straight since up and down don'tever hit bullseye.

2nd Post:

bye I'm going to watch a movie

Do not spam ~billy
Plus do not double post. ¬¬
~L_scorpio

 

someone was making a script a while ago... nothing ever came of it...so i think it would be possible though

 

it is possible and has been made. It's called laser sight.
search it up on google

 

Hmm.. I can't find anything on google... could you PM me a link please?



edit..

Argsorry, just found the link =S

And for all who want it, lookup
"Ultimate Bullseye", program
on google

 

hmm, i tried making soemthing, let me test it out. will post a screenshot in a minute.

 

the laser sight sucks anyways, its only a trial version then you gotta pay real money

 

Inside the swf you can see the formulas on how the shots are calculated; you'd first have to determine the location of the bullseye every turn and then you would have to calculate angle and power to reach that.