Ok, so I have a test tomorrow and I was wondering if someone could help me out on a few problems. 1. The finction T(x)= 200/1+x^2 represents the temerature in degrees Celcius percieved by a person standing x meters away from a fire. a) If the person moves away from the fire at 2m/s, how fast is the temperature changing when the person is 5m away? If someone can help me with this that would be greatly appreciated and +rep Ohh and we're supose to use Leibniz notation.. dy/dx
Yup it's 200/ (1+x²) But I believe in this case the quotient rule needs to be used f'(x)g(x)-f(x)g'(x) /[g(x)]^2 And the answer is suppose to be 5.9
Grant me that I haven't had a need for calculus in a 1 1/2. You need speed in so much as to get where he was at a seconds interval. So, he moves 2 m/s. That means we need to know T(x) = 5 and T(x) = 3. The correct derivation of T(x) = 200(x^2 + 1) is T'(x) = -400*x/(x^4+2*x^2+1) dx/dy. Answer = T'(5) - T'(3) Answer = -400*5/(5^4+2*5^2+1) - (-400*3/(3^4+2*3^2+1)) I'm to lazy to figure it out, but there is the final break down. Good luck.
Used this website to get the correct derivation. Like I said, it's been years, but if your trouble is how to derive the function, then this sight will help with the rules. Just plug in simple versions to figure it out.