How do I put this into 2 equations. I have 6 more $5 bills than $10 bills. In total I have $225. If there are 39 bills in all how many $5 bills do I have. Let x represent the $5 bills and let y represent the $10 bills.
I don't think you can have 39 bills and have 6 more 5s than 10s. If you have 22 5s and 16 10s you have 38 total, and if you have 23 5s and 17 10s you have 40 total.
I don't know how to solve that one. I can come up with a few equations, but none of them work. I dont really understand the purpose of "y" unless you are trying to solve for it and you need to solve for "x" to get the answer. I also don't understand why there should be two equations.
X=5 Y=10 N= Amount of notes N x Y + (N+6) x X = 225 10N+5(N+6)=225 10N+5N+30 =225 15N = 195 N = 13 This question is infact impossible to solve, its possible with 32 bills? Check that isn't a typo?
In your equation you were trying to solve for the value of the bill. :x I did that too when I first tried it. When in doubt, write undefined! XD
How do I put this into 2 equations. I have 6 more $5 bills than $10 bills. In total I have $225. If there are 39 bills in all how many $5 bills do I have. Let x represent the $5 bills and let y represent the $10 bills. x = y + 6 This is because if you have say 3 $10 bills, you will have 3+6 or 9 $5 bills. Which satisfies the first statement. 5x + 10y = 225 This is because each $5 bill is worth 5 and each $10 bill is worth 10, so the total amount of money would be 225, satisfying statement two. There is a third equation, because of statement three. x + y = 39 Now there are two basic ways to solve this, substitution and combination. Unfortunately I have tried solving it and it does not work. Check with your teacher to see if there is a typo or poor instructions or something.