My math homework help corner

Discussion in 'General Discussions' started by asdff, Dec 18, 2006.

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  1. asdff

    asdff Level II

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    Yep just hit me with your math problems and I'll try my best to answer them; just no multivariable calculus or higher please
     
    #1 asdff, Dec 18, 2006
  2. twxlegend

    twxlegend Level III

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    I'm pretty good at maths too, if you like I could be a helper to this board?
     
    #2 twxlegend, Dec 18, 2006
  3. Nessa

    Nessa Level I

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    If someone needs help with multivariable calculus or higher Ill see what I can do, i study engineering :p
     
    #3 Nessa, Dec 18, 2006
  4. asdff

    asdff Level II

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    Yea sure thanks guys :)
     
    #4 asdff, Dec 19, 2006
  5. kkytha

    kkytha Newbie

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    I'm in Year 8 and i've done my GCSE Maths paper 100%

    Can i help too?
     
    #5 kkytha, Dec 19, 2006
  6. asdff

    asdff Level II

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    Of course you don't need permission to help :)
     
    #6 asdff, Dec 20, 2006
  7. kkytha

    kkytha Newbie

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    Yay! C'mon and Hit us with Maths!
     
    #7 kkytha, Dec 20, 2006
  8. twxlegend

    twxlegend Level III

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    Apparently everyone is good at maths here, no one needs any help.^_^
     
    #8 twxlegend, Dec 20, 2006
  9. asdff

    asdff Level II

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    1 + 1 =?
     
    #9 asdff, Dec 20, 2006
  10. twxlegend

    twxlegend Level III

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    2...or is that a trick question? :lol:
     
    #10 twxlegend, Dec 21, 2006
  11. asdff

    asdff Level II

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    I dunno you tell me
     
    #11 asdff, Dec 21, 2006
  12. kkytha

    kkytha Newbie

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    2 over 3a power 4, b power 4 * (-3a power2 b) / 1 over 4a power5, b power7 = ???
     
    #12 kkytha, Dec 21, 2006
  13. asdff

    asdff Level II

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    power 4, b power 4

    Is the comma supposed to be a multiply?
     
    #13 asdff, Dec 21, 2006
  14. Smelly

    Smelly Level IV

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    i woudl ahve thought (x) is multiply.

    maybe 2 differnt q's?
     
    #14 Smelly, Dec 21, 2006
  15. asdff

    asdff Level II

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    Can't be since they can't be simplified any further
     
    #15 asdff, Dec 21, 2006
  16. kkytha

    kkytha Newbie

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    Tis a graph formula

    , is just a way of seperation.
     
    #16 kkytha, Dec 23, 2006
  17. asdff

    asdff Level II

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    Sorry I'm not comprehending- are you being asked to simplify or graph it?
     
    #17 asdff, Dec 24, 2006
  18. unskillful12

    unskillful12 Level III

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    If I have a spherical bowl and I have the radius of the bowl, how do I find the volume of liquid inside of the bowl if the height of the liquid is given? This is for related rates.
     
    #18 unskillful12, Dec 30, 2006
  19. asdff

    asdff Level II

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    Do you mean semispherical? Because a ball is a sphere. Also shouldn't it be the change in volume at a certain height?
    You need to write your volume equation for a half sphere (3/8 pi r^3) then take derivative with respect to time and then plug in your dr/dt, r, and v into that equation. If you give me the problem, I can explain it
     
    #19 asdff, Dec 30, 2006
  20. unskillful12

    unskillful12 Level III

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    Ok the problem (this is from memory):
    It gives you a hemispherical bowl and gives the radius r. It then tells you that water is being poured into the bowl at a certain rate we can call that dv/dt. It wants you to find the rate of change of the height of the water at a particular height h (all variables i mentioned are given). you need dh/dt. The problem for me is i dont know the volume equasion for the water since it does not form a hemisphere until the bowl is full. Is there a ratio or something for the volume of water and the volume of the entire bowl at a given height of the water? thats all i can think of.
     
    #20 unskillful12, Jan 2, 2007
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