Ok, i'm trying to find a domain of a function. Its been like a year since i did the domains of a function, except for my last question. Anyway, find the domain of: F(X)= sqrt((-17x+3)/(-19x-17)) I think i did something wrong, but i can't figure it out. For the domain, i got (-infinity,-17/19)U(-17/19,3/17]. Maybe i did something wrong. So, help again please.
Re: Need help again...math Are you allowed to deal with nonreal #s? If not, then by looking at the denominator, x<(-17/19), which would eliminate the second part of your domain.
Re: Need help again...math You are almost correct... the answer is (-infinity,-17/19)U[3/17,infinity) Just see where the numerator is + or - and where the denominator is + or - numerator: + for x > 3/17, - for x < 3/17, numerator = 0 @ x = 3/17 denominator: + for x < -17/19, - for x > -17/19, denominator = 0 @ x = -17/19 f(x) is defined for when both numerator and denominator have the same sign (or when the numerator is 0)
Re: Need help again...math Too easy. Gee sif u dont get it. LIke, solve this 2+1x2=x I bet you got 6 right? xD
Re: Need help again...math >:[ no need to be mean...and his problem wasn't that easy...the negative signs made it easy to get tripped up, especially if you are doing the problem under time pressure.
Re: Need help again...math (NEW PROBLEMS...HELP PLEASE) second problem: can anyone solve? --- edit: Images of problems...
Re: Need help again...math (NEW PROBLEMS...HELP PLEASE) First question I think answer is C=6. For the function to be continuous, the values of both pieces must be equal at 2, so you plug 2 in for x to get 2C+6 and 4C-6. Then you set them equal, 2C+6=4C-6. From there you solve for C. The second question is the same idea, you plug in -2 for x to get -2m-10 and 4-20-8=-24. So -2m-10=-24, solve for m, giving you m+7. Hope I'm right
Re: Math Help again please (See new post and info) ok... i got some new problems that I'm stuck on. Oh, their are 2 that I just need to see if my answers are correct and 4 that I need help with. I'll give more details after i post them. Answers needed to be checked: ** Note: I'm just one answer off and can't figure it out ** Note: These are the problems that I don't understand. You don't have to do all of them because the last 3 are related so, you only have to explain one of them to me so I can attempt them. ------------------------------------------------------------------------------------------------------ Thanks for all the help guys. Usually the thing that I post are just for checking and if i haven't covered them in the class. This topic will be constantly updated when i have trouble.
Re: Math Help again please (See new post and info) Update: I only need help on 1 problem now and 1 answer check
Re: Math Help again please (See new post and info) If f(x)=root 2x f'(x)=1/(root2x) root 2x = 2x^(1/2) f'(x)=2x^(-1/2) When the power is negative, it implies that the base number is the denominator to 1 (the numerator). EDIT: Dude, stop spamming. If you don't have something worth while to say, don't spam for cash.