Re: ... Are you sure the answer couldn't be undefined or something, because I've tried to work it out several times and unless you want to get radicals involved I don't think it's solvable.
------------------------------------------------------ Factoring polynomials...We did this as review a few chapters ago in class... 15x^2+ 28x +14 If the leading coefficient, the "a" value in quadratic equations, (15 in this case) does not equal 1, then you're going to have a hard time factoring it. The easiest way to factor a polynomial with a leading coefficient > 1 is to find the GCF/Greatest Common Factor. Sadly, The 3 terms in the polynomial don't share a common factor. Though, this particular expression is factorable, as all real expressions are, but it will have a remainder. Basically, you'll have to use synthetic division.
You just have to find the closest perfect square...you'll start to easily spot them. You can also split the number within the square root into factors that have perfect squares. Practice makes perfect. Its better to get this down now rather than later, itll make later math courses 100x easier.
Hahah, that's so true that knowing how to do it will make future math courses a 100x easier XD ... You'll have to solve equations with rational exponents and imaginary radicals...Which isn't too bad actually.
omg..... i hate my teacher right now. (sorry i didnt post before) she gave us that problem and now she tells us that the answer will have a radical in it :x GRRRR' ooh well im probably going to fail the test anyways thanks for the help people ill tell you how i did on the test on wed.